NO LINKS OR FILES ATTACHED OR I WILL HAVE YOU REPORTED I JUST WANT HELP SO NO BS PLS You throw a baseball from 6 feet above the ground with an initial vertical velocity of 38 feet per second. Your friend catches the ball at a height of 2 feet. The equation below models the height of the ball as a function of time. HOW LONG IS THE BALL IN THE AIR? (Round to the nearest hundredth of a second,
y=-16x^(2)+38x+6
You throw a baseball from 6 feet above the ground with an initial vertical velocity of 38 feet per second. Your friend catches the ball at a height of 2 feet. The equation below models the height of the ball as a function of time. FIND THE MAXIMUM HEIGHT OF THE BALL? (Round to the nearest tenth of a foot
y=-16x^(2)+38x+6

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

christopher is 272,195 year old

step-by-step explanation:

its   c, f, a

step-by-step explanation: