William has a coin and a spinner, shown below. He can flip heads or tails on the coin and spin numbers 1 through 8 on the spinner. He flips the coin once and spins the spinner once. What is the probability that the coin will land on heads and the spinner will land on an odd number?

1/4

Step-by-step explanation:

Coin sample Space = {H, T}

Spinner sample space = {1, 2, 3, 4, 5, 6, 7, 8}

Probability that coin lands on head :

P(H) = 1 /2

Probability that spinner lands on odd number :

Odd numbers = {1, 3, 5, 7} = 4

P(spinner lands on odd) = 4 / 8 = 1/2

Hence, probability that the coin will land on heads and the spinner will land on an odd number = (1 /2 * 1/2) = 1/4

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.