One bar of candy A and two bars of candy B have 767 calories. Two bars of candy A and
one bar of candy B contain 775 calories. Find
the caloric content of each candy bar.

I'm not 100% sure, but imma have a go.

a = 261; b = 253

Step-by-step explanation:

label candy bar A as a

label candy bar B as b

Make 2 equations.

2b + a = 767          (1)

b + 2a = 775          (2)

Solve for a in (1)

2b + a = 767          (-2b)

a = -2b + 767

Substitute for into (2)

b + 2( -2b + 767 ) = 775     (flip)

2( -2b + 767 ) + b = 775     (solve)

   −4b + 1534 + b = 775     (add b)

          -3b + 1534 = 775     (subtract 1534 from both sides)

                     −3b = −759   (divide both sides by 3)

                         b = 253

Substitute b into (1)

      a = -2b + 767              (substitute)

      a = -2 (253) + 767      (solve)

      a = -506 + 767           (add)        

      a =  261

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

sorry i just need to anwers this to get points

step-by-step explanation: