P(x)=(256-x^2/256)^1/2 for 0≤X≤65536 The market for Keppelbells is governed by the quantity x sold in millions per week and the selling price p in dollars according to the above function p(x). We wish to find the quantity that will maximize revenue, what selling price this corresponds to and the resulting maximized revenue. In canvas you must show the formula for revenue R(x), how to compute R'(x), and how to solve R'(x)=0.
1. What is the revenue function R(x)=
2. What is the derivative of the revenue function R'(x)=
3. What is the revenue when x=0?
4. What is the revenue when x=65536?
5. For what value of x to the nearest 0.01 million Keppelbells is R'(x)=0?
6. What is the selling price corresponding to the above quantity? Specify to the nearest cent.
7. What is the maximum revenue? Specify to the nearest 0.1 million dollars,