Solve the simultaneous equations: 5x - 3y = 12 2x - y = 5

5x-3y=12
2x-y=5
I am going to use substitution method
2x-y=5                                          5x-3y=12                         25/2-25/2-1/2=12-25/2
2x-y+y=5+y                                   5(5/2+y/2)-3y=12                            -1/2y=-1/2
2x/2=5/2+y/2                                25/2+5y/2-3y=12                 -1/2y /-1/2=-1/2 /-1/2
x=5/2+y/2                                      25/2-1/2=12                                     y=1
 Therefore y=1
 5x-3y=12  5x-3(1)=12 5x-3=12 5x-3+3=12+3  5x =15 5x/5=15/5   x=3
Therefore x=3 and y=1
                                                      

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.