Mathematics, 08.04.2021 20:40 kitkattt1246
Which term of the sequence –3, 1, 5, 9, 13, … is 65?
Alisha solved the question as shown below.
an = 65
a1 = –3
d = –3 – 1 = –4
65 = –3 + (n–1)(–4)
65 = –3 –4n + 4
65 = 1 – 4n
65–1 = 4n
n = 64 ÷ 4
n = 16
So, the 16th term of the sequence is 65.
What is the error in the computation? Find the correct answer.
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Which term of the sequence –3, 1, 5, 9, 13, … is 65?
Alisha solved the question as shown below.
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