Find the numerical value of the log expression. \log a=4\hspace{15px} \log b=9\hspace{15px} \log c=4
loga=4logb=9logc=4
\log \frac{b^7}{a^3c^2}
log
a
3
c
2

b
7

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- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

answer:   y=2x-3

step-by-step explanation:

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}