An aeroplane x whose average speed is 500kmlh leaves Lagos airport at 7:00am nd travel 2hours on a bearing of 050%. If then changes its course nd flies on a bearing of 120% to an airstrip. Another aeroplane leaves Lagos airport at 10:00am nd flies on a straight course to d airstrip A. Both planes arrive at the airstrip A at 11:30am. Calculate a. the average speed of y b .the direction of flight y.​

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to