Pre-Calculus Which is the distance between parallel lines with the equations y=-1/3x+3 and y=-1/3x-7?
A-5 B-3sqrt10 C-sqrt10/7 D-sqrt3

the thermometer is precise but not accurate

step-by-step explanation:

i think asking google will you get the answer to that question

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.