#The extremities of the diagonal of a square are (1,1 )and (-2, -1).Obtain the two other vertices and the equation of a next diagonal. #
find the area of the triangle with vertices(1,2),(2,3),and(4,5).what inference can you draw about the points from your upshot?​

find the area of the triangle with vertices(1,2),(2,3),and(4,5).

(i) (-3/2, 3/2) and (1/2, - 3/2)

6x + 4y = - 3

(ii) Points are col linear

Step-by-step explanation:

Let the coordinates of the point(lower) be (a, b) and that of upper be (x, y).

Using mid point formula,

Mid point of diagonal(using the given points) is:

= ( (-2+1)/2 , (-1+1)/2) = (-½ , 0)

Using (a, b) and (x, y) :

= ( (a+x)/2 , (b+y)/2 ) = (-1/2, 0)

Which means, a+x= -1 & b + y = 0

Therefore, x = - 1 - a & b = - y

Using distance formula, diagonal = √(-2-1)² + (-1-1)² = √13

Knowing the relation in diagonal and side, side = diagonal/√2 = √13/√2 = √(13/2)

Again using distance formula, diagonal = √13

=> √(x - a)² + (y - b)² = √13

=> (-1-a -a)² + (-b - b)² = 13

=> a² + b² + a = 3 ... (1) [solved directly]

Length of side = √(13/2)

=> √(a-(-2))² + (b-(-1))² = √(13/2)

=> a² + b² + 4a + 2b = 3/2 ...(2)

On solving (1) and (2):

a = 1/2 or -3/2, but a lies in 4th quadrant so a > 0, thus, a = 1/2

b = -3/2 or 3/2, but b lies in 4th quadrant so b < 0, b = -3/2

Therefore,

x = - 1 - a = -1 - 1/2 = -3/2

y = - b = - (-3/2) = 3/2

Vertices are (x, y) = (-3/2, 3/2) and (a, b) = (1/2, -3/2)

Equation is just a relation in y and x, for a relation:

Subtract (1) from (2):

3a + 2b = -3/2 => 6a + 4b = - 3

By merely replacing a, b by x, y

6x + 4y = -3 is the required equation

(ii):

Ar. of ∆ = ½ | 1(3 - 5) + 2(5 - 2) + 4(2 - 3) |

Ar. of ∆ = ½ | -2 + 6 - 4 | = 0

As the area of the ∆ is 0, the given points don't form ∆, they are col linear.

i want to die

what the hell man, i just want the points lol

answer: e 9, 5.75

step-by-step explanation:

step 1

find the variation ab in the x coordinate

delta x=(x2-x1)=10-> 8 units

find the variation ab  in the y coordinate 

delta y=(y2-y1)=6-> 2 units

step 2

find the coordinates point c

  x coordinate 

cx=ax+delta x*2/> cx=2+8*(2/> cx=3

  y coordinate 

cy=ay+delta y*2/> cy=4+2*(2/> cy=4.25

the coordinates of point c are (3,4.25)

step 3

find the coordinates point d

  x  coordinate 

dx=ax+delta x*4/> dx=2+8*(4/> dx=4

  y  coordinate 

dy=ay+delta y*4/> dy=4+2*(4/> dy=4.5

the coordinates of point d are (4, 4.5)

step 4

find the coordinates point e

  x  coordinate 

ex=ax+delta x*4/> ex=2+8*(6/> ex=5

  y  coordinate 

ey=ay+delta y*4/> ey=4+2*(6/> ey=4.75

the coordinates of point e are (5, 4.75)

step 5

find the coordinates point f

  x  coordinate 

fx=ax+delta x*4/> fx=2+8*(8/> fx=6

  y  coordinate 

fy=ay+delta y*4/> fy=4+2*(8/> fy=5

the coordinates of point f are (6,5)

step 6

find the coordinates point g

  x  coordinate 

gx=ax+delta x*4/> gx=2+8*(10/> gx=7

  y  coordinate 

gy=ay+delta y*4/> gy=4+2*(10/> gy=5.25

the coordinates of point g are (7,5.25)

step 7

find the coordinates point h

  x  coordinate 

hx=ax+delta x*4/> hx=2+8*(12/> hx=8

  y  coordinate 

hy=ay+delta y*4/> hy=4+2*(12/> hy=5.5

the coordinates of point h are (8,5.5)

step 8

find the coordinates point i

  x  coordinate 

ix=ax+delta x*4/> ix=2+8*(14/> ix=9

  y  coordinate 

iy=ay+delta y*4/> iy=4+2*(14/> iy=5.75

the coordinates of point i are (9,5.75)

- r3ktforgood ☕