A surveyor holds a laser range finder 3 feet above the ground and determines that the range finder is 92 feet from a building and 106 feet from the top of the building. What is the height h of the building? Round your answer to the nearest tenth.

55.64

Step-by-step explanation:

The range finder is 92 feet from the building and 106 feet from the top of the building i.e. hypotheses

We will use the Pythagorean theorem:

x^2 = 106^2 - 92^2

= 11,236 -  8,464

= 2,772

= √2,772

x = 52.64978632

The height of the building:

h = x + 3

= 52.64978632 + 3

= 55.64978632

or

≈ 55.64 feet

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answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204