I have to find the problem using this process. Can somebody please help me

Length = 13 in

Width = 10 in

Step-by-step explanation:

Let L be the length.

Let W be te width.

From the question given above, the Lenght is 3 more that the width i.e

L = 3 + W

Next, we shall determine the width (W). This can be obtained as follow:

Length (L) = 3 + W

Width (W) = W

Area (A) = 130 in²

A = L × W

130 = (3 + W) × W

Clear bracket

130 = 3W + W²

Rearrange

W² + 3W – 130 = 0

Solving by formula method

W = –b ± √(b² – 4ac) / 2a

a = 1

b = 3

c = –130

W = –3 ± √(3² – 4 × 1 × –130) / 2 × 1

W = –3 ± √(9 + 520) / 2

W = –3 ± √(529) / 2

W = –3 ± 23 / 2

W = –3 + 23 / 2 or –3 – 23 / 2

W = 20/2 or –26/2

W = 10 or –13

Since measurement can not be negative, the width is 10 in.

Finally, we shall determine the length. This can be obtained as follow:

L = 3 + W

W = 10

L = 3 + 10

L = 13 in

SUMMARY

Length = 13 in

Width = 10 in

i believe the correct answer is b.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58