Farmer ed has 7000 meters of fencing and wants to enclose a rectangular plot that borders on a river. if farmer ed does not fence the side along the river, what is the largest are that can be enclosed?

Let

x--------> the length side of the rectangular plot (assume side along the river)

y------> the width side of the rectangular plot

we know that

the perimeter of the rectangular plot is equal to

so

Clear variable y

-------> equation

The area of the rectangular plot is

------> equation

substitute equation in equation

we know that

To find the larger area that can be enclosed------> Find the vertex of the quadratic equation

The quadratic equation is a vertical parabola open down

so

the vertex is a maximum

using a graphing tool

see the attached figure

the vertex is the point

that means

For

the largest area is

Find the value of y

the dimensions of the rectangular plot are

therefore

the answer is

The largest area that can be enclosed is

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !