If ab=8 and a^2+b^2=16 then what is the valué of (a+b)^2 PLSS HELP NOW

I think that i got it but at the same time not sure but the value of a+b should be 14+20

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: