The half-life of a certain radioactive substance is 14 days. There are 6.6g present initally. Express the amount of substance remaining after 28 days A) f(t)=6.6(12)2
B) f(t)=14(12)t6.6
C) f(t)=14(12)6.6t
D) f(t)=6.6(12)28

B) f(t)=14(12)t6.6

Step-by-step explanation:

I just multiply it and convert

CarryOnLerning

f(t) is the amount of substance remaining.

f(t) = 6.6 × 12 × 28.

Correct choice - [D] f(t) = 6.6(12)28.

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !