Here is a sample data set that appears to be nearly normal (as suggested by the histogram). 69.8 86.4 66 80.7 66.5 62.4 79.4
72 74.4 62.5 64.6 68.4 66 81.8
73.5 80.7 71.6 55.5 65.6 76.5 63.5
74.7 69.6 76.2 | 67.1 73 65.3 61
88.4 80.771.4 84 75.1 53.668
73.3 72.9 62.7 76.9 61.4 66.3 72.9
54.3 64.9 72.9 65.6 74 71.8 64.3
67.1 | 66.7 62.4 72 70.6 63.5 81.2
60.6 | 74.7 57.6 82.476.5 74.9 59.7
75.1 68.6 71.6 57.6 71.2 71.2 70.2
20
15
Frequency
10
50 55 60 65 70 75 80 85 90
length (cm)

i think is g(1)=-1.

hope that i can

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.