Which function has zeros of -8,1, and 3

A

Step-by-step explanation:

The zeros of a polynomial function are found by factoring in the form

a(x - r1)(x - r2)(x - r3) ... = 0, where each 'r-something' is a root (or solution) and 'a' is the leading coefficient.

Like if we have 3x² - 3x - 6 = 0

Factoring it as 3(x-2)(x + 1) = 0 shows the roots are 2 and -1.

And sine the right side is zero, we can even drop the factor of 3 on the left, and still have an equivalent equation (has same answers).

(x-2)(x + 1) = 0

The reason this works is because each factor in parentheses adds up to zero, creating a factor of zero in what is being multiplied on the left. And we know that if you have a series of factors in a product, and any one of those factors is zero, the whole product must be zero. So what is on the left equals the zero on the right, making the equation true.

answer: the common difference is -0.10

afjnawenkfnjaw; enkanwelwaklalejjaw; fij

step-by-step explanation: