Please help.. j
Graph h(x) = 2 sin (2x) - 3.

Use 3.14 for it.

Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum
value on the graph closest to the first point.

Step-by-step explanation:

The midline is when y = -3, since that is the constant you are adding. This occurs when sin(2x) = 0, which occurs at x = 0. Here, the first point on the midline would be (0,-3).

To solve for a maximum, we need to find a value of x in which sin(2x) = 1. This occurs at pi/4, meaning we have a maximum at (pi/4, -1).

The next point would also be on the midline at pi/2, which would be (pi/2, -3).

The minimum would occur at 3pi/4 (since the sine would be -1), and the point would be (3pi/4, -5).

The last point of a 5-point summary would also be on the midline, at x = pi, (since the sine would be 0), and the point would be (pi, 0).

After this =, the sine tool function should sketch the rest of the graph.  

i use my brain for prombles like this maybe you could try it

step-by-step explanation: