If AC=22 BC=19 in a figure what is the radius?

11.09units

Step-by-step explanation:

Find the diagram attached

The radius of the circle is line projecting from the center to the circumference. Hence AB is the radius of the circle.

To get AB, we will use the pythagoras theorem as shown;

Given

AC=22

BC=19

AC² = AB²+BC²

22² = AB²+19²

AB² = 22²-19²

AB² = 484-361

AB² = 123

AB = √123

AB = 11.09

Hence the radius of the circle is 11.09units

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3