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1) v_i = 2.78 m/s

v_f = 16.67 m/s

t = 5 s

Acceleration = 2.78 m/s²

2) a = 1.5 m/s²

Step-by-step explanation:

1) The car was running at 10 km/hr.

In m/s this is 2.78 m/s

Thus;

Initial velocity; v_i = 2.78 m/s

It increased its speed to 60 km/hr in 5 seconds.

Thus, final velocity is 60 km/hr

Converting to m/s gives; 16.67 m/s

Final velocity; v_f = 16.67 m/s

Time to reach final velocity; t = 5 seconds

From Newton's first equation of motion, we can find the acceleration;

a = (v_f - v_i)/t

a = (16.67 - 2.78)/5

a = 2.78 m/s²

2) started from test, so initial velocity;

v_i = 0 m/s

Reached a speed of 9 m/s in 6 seconds.

Final velocity; v_f = 9 m/s

Time; t = 6 s

Acceleration is calculated as;

a = (v_f - v_i)/t

a = (9 - 0)/6

a = 1.5 m/s²