Ridzuan jogs in the morning for every 4 days and plays badminton in the evening for every 6
days. If on a particular day, Ridzuan jogs in the
morning and plays badminton in the evening, how
many days later would he jog and play badminton
again on the same day?​

24 days

Step-by-step explanation:

Jogs every 4 days

Badminton every 6 days

If on a particular day, Ridzuan jogs in the

morning and plays badminton in the evening, how

many days later would he jog and play badminton

again on the same day?

Find the lowest common multiple of 4 days and 6 days

4 days = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52

6 days = 6, 12, 18, 24, 30, 36, 42, 48, 54

The lowest common multiple of 4 days and 6 days is 24 days

It would take Ridzuan 24 days before he would jog and play badminton again on the same day

i will take them

step-by-step explanation:

center= (-2,0)

radius= sqrt2/2

step-by-step explanation: