How do you prove that a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects? will ACTUALLY GIVE YOU AND EVERYTHING​

Step-by-step explanation:

If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment. If CP is the perpendicular bisector of AB, then CA = CB. If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.

Consider the line segment AB,

let M be the midpoint of AB, so AM=MA

erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B

The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:

AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB

so PA=PB

Explanation: If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment. If CP is the perpendicular bisector of AB, then CA = CB. If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.

Brailiest is appreciated

to rewrite a literal equation you may need to divide by a number, or by a variable.

hope i .

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: