PLEASE HELP THIS IS MY LAST QUESTION! Triangle JKL is an equilateral triangle with two of its vertices at points J and K. What are the coordinates of point L? Round to the nearest tenth as needed.

(6, 7.2)

Step-by-step explanation:

Since it is an equilateral triangle, all of the side length must be equal.

Therefore, we know the lengths JK = 6 and JL = 6. If h is the height of the triangle, the Pythagoras's theorem says

(JK/2)² + h² = JL²

putting in the values of JK and JL gives

(6/2)² + h² = 6²

3² + h² = 6²

subtracting 3^2 from both sides gives

h² = 6² - 3²

h² = 27

Taking the square root of both sides gives

h =

h = 5.2

With the value of h in hand, we can now read off the coordinates of L.

The x coordinates of L is 6 (count the boxes along the x-axis until you are under L or halfway between J and K).

The y-coordinates of L is 2 + h = 2 + 5.2 = 7.2 ( how far above the x-axis the triangle is plus the height of the triangle).

where are the choices?