Henri has $24000 invested in stocks and bonds. The amount in stocks is $6000 more than three times the amount in bonds. Call the amount that henri invested in stocks s and the amount he invested in bonds b

Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

Step-by-step explanation:

Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:

6000 + 3B + B = 24000

3B + B = 24000 - 6000

4B = 18000

B = 18000/4

B = 4500

S = 6000 + 3x4500

S = 6000 + 13500

S = 19500

Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

step-by-step explanation:

a child is 12 years old, and his father is 32 years older. in how many years will the age of the father be 2 times the age of the child?

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this needs to be the answer format, or else your answer is incomplete.

if the number of years is x, then the equation is

in __ years

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.