Acompany sells t-shirts for $11 each and sweatshirts for $19 each. the number of t-shirts sold was 10 fewer than three times the number of sweatshirts sold. the t-shirts and sweatshirts sold for a total of $1,970. how many t-shirts were sold?

110 T-shirts were sold

Step-by-step explanation:

Let x represents the number  T-shirts and y represents the number of sweatshirts.

As per the statement:

A company sells T-shirts for $11 each and sweatshirts for $19 each

⇒Cost of x T-shirts = 11x

and Cost of y -sweatshirt  = 19y

The number of T-shirts sold was 10 fewer than three times the number of sweatshirts sold.

⇒x = 3y -10             ......[1]

It is also given that:

The T-shirts and sweatshirts sold for a total of $1,970.

⇒            .....[2]

Substitute equation [1] into [2] we have;

Using distributive property,

Combine like terms;

52y - 110 = 1970

Add 110 to both sides we have;

52y = 2080

Divide both sides by 52 we have;

y = 40

Substitute in [1] we have;

x = 3(40) -10

x = 120-10 = 110

⇒x = 110

therefore, 110 number of  T-shirts were sold

x=half

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb