Ashlee was born on 12/24/2002. How many eight-digit codes could she make using the digits in her birthday?

840

Step-by-step explanation:

Given the date:

Birth date = 12/24/2002

Number of digits = 8 = 8! = (8*7*6*5*4*3*2*1) = 40320

Repeated digits :

digit 2 = 4 times = 4! = (4 * 3 *2 * 1) = 24

digit 0 = 2 times = 2! = 2*1 = 2

Therefore the number of 8 digit codes that can be formed is :

8! / (4! * 2!)

40320 / (24 * 2)

40320 / 48

= 840

Hence, 840 8 digit codes can be formed

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step-by-step explanation: