A ball is dropped from a height of 64 feet. Its height, in feet, can be modeled by the function h(t) = -16t2 + 64, where t is the time in seconds since the ball was dropped. A. After how many seconds will the ball hit the ground? B. What is a reasonable domain and range for this function?

See solution below

Step-by-step explanation:

The ball will hit the ground at whrn t = 0

Given the height of the ball modeled by the expression

h(t) = -16t^2 + 64

0 =  -16t^2 + 64

16t^2 = 64

t^2 = 64/16

t^2 = 4

t = 2sec

The ball will hit the ground 2secs after

The domain are the values of the input values t and this values start from 2 and greater. Hence the domain of the function is {2, ∞}

when t = 2

h (2) = -16(2)^2 + 64

h(2) = -64+64

h(2) = 0

Hence the range are the output values i.e the height.

The range are within the range {0, ∞}

one way is to plot 2 points and connect them which is what the answer choices seem to be doing

it seems to be using the y intercept and the slope

y=mx+b, m=slope, b=y-intercept (where the line hits the y axis)

slope=rise/run

y-intercept is where the line croses the y axis which is the y value where x=0

you seem to have given the wrong slope (you didn't put a number in front of te x, it should be 2/3 or 3/2 looking at the answer options)

y=? x-1

m=? because of your fault

b=-1

so it has a slope of ? and y intercept of -1, meaning it pases through (0,-1)

so draw point (0,-1) (so answer is one of the first 2 option)

if slope is 2/3, then go up 2 and right 3 then draw line through those 2 points

if slope is 3/2, then go up 3 and right 2 then draw line through those 2 points