For number 4 because it has select, the select are first one under C) 66, 64, 67, 65
under B) 24, 23, 26, 25
under A) 15, 16, 17, 18
lowest under C) 40, 41, 42, 39
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also this one: Which of the following represents a Pythagorean Triple?
Group of answer choices

{21, 72, 75}

{11, 45, 60}

{5, 7, 10}

{10, 20, 30}

I only know the first one for right now and the answer is 17

Step-by-step explanation:

You got to find the value of x in the figure

To do that, you have to apply Pythagorea theorm: hyp^2=a^2+b^2. where a and b are legs of the triangle. Hyp=hypotenuse. So in conclusion you have this: x^2=8^2+15^2

x^2=64+225

x^2=289

Then it's x= 289 like this

Which gives you the answer 17

Let me know if this helps

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)