Mathematics, 01.04.2021 15:40 marrizza7

C. x2 + y2 – 3x – 10y + 9 = 0 D. x2 + y2 - 8x - 6y - 15 = 0
E.
2015/16, Q37
The ends of a diameter of a circle have coordinates (5,4) and (-3,6). The equation of the circle is given as:
A. x² + y2 – 2x – 10y + 9 = 0 B. x2 + y2 - 2x - 9y + 10 = 0
C. x2 + y2 – 3x – 10y + 9 = 0 D. x2 + y2 – 3x - 9y + 10 = 0 E.
2015/16,
Q43
The equation of the tangent to the circle x2 + y2 + 2x - 3y = -1 at the point (3, 4) is given as:
A. 5x + 8y - 4 = 0 B. 8x + 5y -4 = 0 C. 2x - 9y + 12 = 0 D. 2x + 9y + 10 = 0 E.
2015/16, Q48
A. 2x – y + 12 = 0
The equation of the tangent to the circle x2 + y2 + 3x - 2y = 0 at the point (3,2) is given as:
B. X – 9y + 12 = 0 C. 2x - 9y + 12 = 0 D. 2x - 9y + 10 = 0 E
NICY
2015/16,
Q52

Answers: 1

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C. x2 + y2 – 3x – 10y + 9 = 0 D. x2 + y2 - 8x - 6y - 15 = 0
E.
2015/16, Q37
The ends...