Find the area of the figure. 8 m
15 m
Rounded to the nearest tenth, the area is
square meters.

145.1 square meters

Step-by-step explanation:

The figure is composed of a rectangle and a semicircle.

Therefore, area of the figure = area of the rectangle + area of the semicircle

✔️Area of the rectangle = L*W

L = 15 m

W = 8 m

Area of rectangle = 15*8 = 120 m²

✔️Area of semicircle = ½(πr²)

r = ½ of 8 = 4 m

Area of semicircle = ½*π*4²

Area of semicircle = 25.1327413 m²

✔️Area of the figure = 120 + 25.1327413 = 145.132741 ≈ 145.1 m² (nearest tenth)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this