How many different 5-digit codes could we make if numbers could be repeated?

Now start again with 2 as the first digit. The smallest is 21345, the largest is 25431 and again there are 24 possibilities. Repeat this process again with 3 as the first digit, then 4 as the first digit and finally 5 as the first digit. In total you will find 5 × 24 = 120 possibilities.

Step-by-step explanation:

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x