Mr. Chamberlain is planning a field trip for his math classes to visit a museum. It costs $300 to rent the bus, then $7.50 per student for entry to the museum Mr. Chamberlain only has a budget of $1,000 from the school. Which equality below represents the number of students he can bring on the trip?

Equation - $1000=$300+$7.50x

Answer - Mr. Chamberlain can included 93 Student Entries

Step-by-step explanation:

$1000 (budget)

$300 (cost to rent bus)

$7.50 (cost of each student entry)

$1000-$300= $700

Now we have found out that Mr. Chamberlain has $700 left to spend on student entries.

$700/$7.50 = 93.333

Round 93.333 down to 93 because you can't have 1/3 of a student (obviously)

93 = the max number of student entries that Mr. Chamberlain can have for the museum field trip

I hope this helps :)

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