Y ∝
1
√
x
If
y
=
7
when
x
=
64
find,
x
when
y
=
8

x = 49

Step-by-step explanation:

This is an inverse relationship and it implies that, an increase in the value of one variable results in a subsequent decrease in the value of another variable.

Given the mathematical expression and data;

y = 1/√x

y = 7 and x = 64

First of all, we would find the constant of proportionality, k;

y = k/√x

7 = k/√64

7 = k/8

k = 7 * 8

Constant, k = 56

Now, to find the value of x when y = 8

y = k/√x

Substituting the values, we have;

8 = 56/√x

Cross-multiplying, we have;

8 * √x = 56

√x = 56/8

√x = 7

Taking the square of both sides, we have;

(√x)² = 7²

x = 49

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

mx+89b(-98)nb

step-by-step explanation: