If X and Y are independent random variables with variances o^2 (X) = 8 and o^2 (Y) = 5, find the variance of the random variable Z = -8X + 4Y – 6.​

answer:  

\boxed {\frac{1}{5}}  

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solution-

60 *   \frac{1}{5}   = 12

90 * \frac{1}{5} = 18

75 * \frac{1}{5} = 15

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hence, the answer would be \boxed {\frac{1}{5}}