A sugar box manufacturing company is accurately making 100 g packets. Suppose a business researcher randomly selects 100 boxes, weighs each of them and computes its mean. Due to non-random selection or by chance, a researcher selects packets that have not been adequately filled and that is how he gets the mean weight of 98 g, which falls in the rejection region. The decision is to reject the null hypothesis even though the population mean is actually 100 g. Which kind of error has the researcher done in this case

The kind of error the researcher has done is a;

Type I error

Step-by-step explanation:

When carrying out hypothesis testing in statistical analysis, a type I error is the type of error said to have occurred when a null hypothesis that is true or correct is rejected which is a false positive conclusion

Given that that sugar box manufacturing company makes the boxes to be 100 g accurately, and that the researcher makes non-random or randomly selects packets which are not filled, the mean of the filled packets is expected to be 100 g making the conclusion for rejection of the null hypothesis a false positive rejection

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2