Mathematics, 29.03.2021 23:40 chgraypto

The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve. x + y = 0
x^2 - y^2 = -2
x^2 + y^2 = 16
x^2 + y^2 = 8

Answers: 2

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The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve. x + y = 0 x^2 - y^2 = -2 x^2 + y^2 = 16 x^2 + y^2 = 8

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The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve. x + y = 0
x^2 - y^2 = -2
x^2 + y^2 = 16
x^2 + y^2 = 8