EDG-ENUITY MATH 9TH GRADE MARCH 29: ANSWERS IF YALL NEED HELP WITH ANYTHING HIT THE HEART ON MY PROFILE TO NOTIFIE ME THEN TELL ME WHAT U NEED. THIS MEANS CORRECT <<<<< the arrows What are the values of the coefficients and constant term of 0 = 4 – 7x2 + x in standard form?

a = -7

b = 1

c = 4

Which equations have a leading coefficient of 3 and a constant term of –2? Check all that apply.

0 = 3x2 + 2x – 2<<<<<<

0 = –2 – 3x2 + 3

0 = –3x + 3x2 – 2<<<<<<

0 = 3x2 + x + 2

0 = –1x – 2 + 3x2<<<<<<

Two of the steps in the derivation of the quadratic formula are shown below.

Step 6: StartFraction b squared minus 4 a c Over 4 a squared EndFraction = (x + StartFraction b Over 2 a EndFraction) squared

Step 7: StartFraction plus or minus StartRoot b squared minus 4 a c EndRoot Over 1 a EndFraction = x + StartFraction b Over 2 a EndFraction

Which operation is performed in the derivation of the quadratic formula moving from Step 6 to Step 7?

subtracting StartFraction b Over 2 a EndFraction from both sides of the equation

squaring both sides of the equation

taking the square root of both sides of the equation<<<<<
taking the square root of the discriminant

The discriminant of a quadratic equation is the value b2 – 4ac. What is the value of the discriminant of 0 = –2x2 + 6x + 13?

140<<<<

Consider the function f(x) = 3x2 + 7x + 2.

What is the value of the discriminant?

✔ 25

How many x-intercepts does this function have?

✔ 2

What are the number of zeros for this function?

two real numbers<

Which graph shows a quadratic function with a discriminant value of 0?

its D<<<

Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? Check all that apply.

-5 and -9/2

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?

–5<<<<<

–3

3

4

Describe how to derive the quadratic formula from a quadratic equation in standard form

The quadratic formula is derived from a quadratic equation in standard form when solving for x by completing the square. The steps involve creating a perfect square trinomial, isolating the trinomial, and taking the square root of both sides. The variable is then isolated to give the solutions to the equation.

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