![\sqrt[3]{x+4}+\sqrt[3]{2x +8}=0\\\\\sqrt[3]{x+4}= -\sqrt[3]{2x + 8}\\\\(x +4)^{\frac{1}{3}}=-(2x+8)^{\frac{1}{3}}\\\\](/tpl/images/2257/8495/c3ced.png)
![[(x+4)^{\frac{1}{3}}]^{3} =- [(2x +8)^{\frac{1}{3}}^{3}]\\\\(x+4)^{3*\frac{1}{3}}=-(2x + 8)^{3*\frac{1}{3}}\\\\](/tpl/images/2257/8495/45014.png)
What is the solution to the equation?
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Mathematics, 29.03.2021 17:10 karen4764
What is the solution to the equation?
Answers: 1
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