HELP PLEASE AND NO LINKS The length of a rectangle is twice its width. Given the length of the diagonal is $5\sqrt{5}$, find the area of the rectangle.

Step-by-step explanation:

Width =x

Length = 2*x = 2x

Diagonal = 5√5

Use Pythagorean theorem

Length² + Width² = diagonal²

  (2x)²    + x²        = (5√5)²      

{}

     4x²   + x²        = 75

                      5x² = 75

                        x²  = 75/5

                       x²   = 15

                        x = √15

Width = √15

Length = 2√15

Area of rectangle = length *width

                             = √15 *2√15

                             = 30 square units

i'm assuming it's looking for the missing length, which should be 4cm

hope this !

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8