Find the third degree polynomial function that has an output of 40 when x=1, and has zeros −19 and −i?

Step-by-step explanation:

Complex numbers:

The following relation is important for complex numbers:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots such that it can be written as: , in which a is the leading coefficient.

Has zeros −19 and −i

If -i is a zero, its conjugate i is also a zero. So

Output of 40 when x=1

This means that when . We use this to find the leading coefficient a. So

The polynomial is:

what?

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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