1. Write the slope-intercept form of the equation that passes through the point (0, 1) and is parallel to the line y = 3x - 5 O y = 3x + 1
O y = 3x - 4
O y = -1/3x - 4
O y = -1/3x + 1

y = 3x + 1

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is Y = 3X - 5. Its slope is 3. A line parallel to this one will also have a slope of 3.

Plug this value (3) into your standard point-slope equation of y = mx + b.

y = 3x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (0, 1). Plug in the x and y values into the x and y of the standard equation.

1 = 3(0) + b

To find b, multiply the slope and the input of x (0)

1 = 0 + b

Now, add 0 to both sides to isolate b.

1 = b

Plug this into your standard equation.

y = 3x + 1

This equation is parallel to your given equation (y = 3x - 5) and contains point (0, 1)

Hope this helps!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

is only a line? i think so