Consider again the tossing of a pair of dice. Find the probability the sum is greater than 6. (Round to the hundredths)

7/12 or 58.333%

Step-by-step explanation:

There are the 36 possible outcomes.  

6+5+4+3+2+1 = 21 are greater than 6  

Probability is 21/36 = 7/12 or 58.333%

see several wrong answers posted (and one correct answer so far), so I will try to present the correct solution.

Total number of possibilities is 36 (6 x 6), two six sided dice.

Of these possibilities, 21 are greater than 6, listed here: 6 ways to roll a 7, 5 ways to roll an 8, 4 ways to roll a 9, 3 ways to roll a 10, 2 ways to roll an 11, and 1 way to roll a 12.

These are the qualifying rolls: (1,6),(2,5),(2,6),(3,4),(3,5),(3,6),(4,3),(4,4),(4,5),(4,6),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) - 21 total sums over 6

So the probability is 21/36, or simplifying, 7/12. Converted to a percentage, it is 58.333%.

boxplot

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: