The line 1 has equation 5x + 6y + 30 = 0. Given that P is the point (3, -1), find
(i) the coordinates of the point where l crosses the
x-axis,
(ii) the coordinates of the point of intersection
of l with the line x = 2,
(iii) the equation of the line passing through P
and having the same gradient as I,
(iv) the equation of the line passing through P
and having a gradient of 0.
w through the points ACO 3).

Step-by-step explanation:

i) the x-intercept is when y=0

5x+6(0)+30=0

5x=-30

x=-6

hence the point is (-6,0)

ii)5(2)+6y+30=0

10+6y+30=0

6y=-40

y=-20/3

hence the point of intersection is (2,-20/3)

iii) y+1=-5/6(x-3)

6y+6=-5x+15

6y+5x=9

iv) y+1=0(x-3)

y=-1

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm