From a random sample of 185 children from school G, 108 indicated they wanted to study science in college. From a different random sample of 165 children from school H, 92 indicated they wanted to study science in college. Assuming all conditions for inference are met, which of the following is closest to the standard error for a confidence interval for the difference in population proportions between the two schools of children who want to study science in college?A. 1.96 underroot(200/350)(1 − 200/350)/350.B. Underroot(108/185)(1 − 108/185)185 − (92/165)(1−92/165)/165.C. Underroot(108/185)(1 − 108/185)185 + (92/165)(1−92/165)165.D 1.96 underroot(108/185)(1 − 108/185)185 + (92/165)(1 − 92/165)165.E. Underroot(200/300)(1 - 200/300)/350.

C. Underroot(108/185)(1 − 108/185)185 + (92/165)(1−92/165)165.

Step-by-step explanation:

Sample size, n1 = 185

x1, = 108

P1 = x1 / n1 = 108 / 185 =

Sample size, n2 = 165

x2, = 92

P2 = x2 / n2 = 92/165

Standard Error = sqrt[(p1(1-p1))/n1 + (p2(1-p2))/n2]

sqrt[(108/185(1 - 108/185)) /185 + (92/165(1 - 92/165)) / 165]

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.