Two number cubes are rolled. What is the probability that the first lands on an odd number and the second lands on an even number?

Enter you answer, as a fraction in simplified form, in the box

1/4

Step-by-step explanation:

Assuming the number cube is a six-faced die, you have

1 2 3 4 5 6

three odd numbers, and three even numbers. Therefore, the chance of it landing on an odd number or even number is 3/6, which equals 1/2. That means you have a 50% chance to get an odd number, or an even number.

So, you have two die. Both have a 50/50 chance of getting an even or odd number. So what's the chance of one landing on an odd number, and the other landing on an even number?

25% as a simplified fraction is 1/4. Therefore, 1/4 is your answer.

step-by-step explanation:

see if this :

a is the right answer