There are three cabinets, a, b, and c, each of which has 2 drawers. each drawer has 1 coin: a has 2 gold coins, b has 2 silver coins and c has 1 silver and one gold coin. a cabinet is chosen at random, one drawer is opened and a silver coin is found. what is the probability that the other drawer in that cabinet contains a silver coin?

i think the answer is b

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.