Z^m-n (z^m+ z^m+n + z^n)

Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:

(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

1=(−1)2n=[(−1)n]2 which is always true, no matter what n is

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/