PLS HURRY I WILL GIVE BRANLIEST AND LOTS OF POINTS A rectangular city lot has an area of 1,000 square meters. If the length of the lot is 10 meters more than twice its width, find the length and width. Write the quadratic equation.

The closest thing that i could come up with was 27 x 37... It equals 999 Hope this helps

Step-by-step explanation:

Length of the Area = 50mtrs

Width of the Area  = 20mtrs

Step-by-step explanation: Let the x be the length and y be the width of the Area. So we can write x = 2 y + 10 and x y = 1000 or ( 2 y + 10 ) y = 1000 or 2 y 2 + 10 y = 1000 or 2 y 2 + 10 y − 1000 = 0 or y 2 + 5 y − 500 = 0 or y 2 + 25 y − 20 y − 500 = 0 or y ( y + 25 ) − 20 ( y + 25 ) = 0 or ( y + 25 ) ( y − 20 ) = 0 or y + 25 = 0 or y − 20 = 0 or y = − 25 Invalid value contains negative sign or y = 20 So Width of the Area is 20 Ans By plugging the value of y = 20 in the eqn x = 2 y + 10 we get Length of the Area = 2 × 20 + 10 = 50 Ans

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5