Where do the graphs of y = 4x - 3 and y = 9x - 13 intersect?
Someone help me asap plz!

(2, 5 )

Step-by-step explanation:

To find the point of intersection, solve the equations simultaneously.

y = 4x - 3 → (1)

y = 9x - 13 → (2)

Substitute y = 9x - 13 into (1)

9x - 13 = 4x - 3 ( subtract 4x from both sides )

5x - 13 = - 3 ( add 13 to both sides )

5x = 10 ( divide both sides by 5 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (1)

y = 4(2) - 3 = 8 - 3 = 5

point of intersection = (2, 5 )

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)