You watched a movie that lasted 2 2 /3 hours and then went out to eat for 2 3 /4 hours. How many hours in all did the movie and dinner last? If the movie started at 3:00, what time did you finish eating?

Step-by-step explanation:

Add together:  2 2/3 hrs and 2 3/4 hrs:

First determine the LCD of these two fractions.  The LCD here is 3*4 = 12.

Rewrite the given times using this LCD:

2 8/12 + 2 9/12

Adding 2 and 2 results in 4; adding 8/12 and 9/12 results in 17/12, or 1 5/12.

The final result is 4 + 1 5/12, or 5 5/12.

The movie and dinner together lasted 5 5/12 hrs.

If movie and dinner started at 3:00, dinner would have finished at

3:00 + 5:5/12, or

8:25 p.m. (since 5:5/12 is the same as 5:25).

Finished eating at 8:25 p.m.

Finished eating at 8:25 and both lasted 5:25 hours in total

Step-by-step explanation:

first one because it can't have a fraction in it

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92